Students Marks Sum in C - Hackerrank Solution

You are given an array of integers,

, denoting the marks scored by students in a class.

The alternating elements , , and so on denote the marks of boys.
Similarly, , , and so on denote the marks of girls.

The array name,

, works as a pointer which stores the base address of that array. In other words,

contains the address where

is stored in the memory.

For example, let

and

stores 0x7fff9575c05f. Then, 0x7fff9575c05f is the memory address of

Complete the function, marks_summation(int* marks, char gender, int number_of_students) which returns the total sum of:

marks of boys if
marks of girls if

The locked code stub reads the elements of

along with

. Then, it calls the function marks_summation(marks, gender, number_of_students) to get the sum of alternate elements as explained above and then prints the sum.

Input Format

The first line contains , denoting the number of students in the class, hence the number of elements in .
Each of the subsequent lines contains .
The next line contains .

Constraints

(where )
= or

Output Format

The output should contain the sum of all the aternate elements in

as explained above.

Sample Input 0

Sample Output 0

Explanation 0

= [3, 2, 5] and

So,

Sample Input 1

Sample Output 1

Explanation 1

= [1, 2, 3, 4, 5] and

So,

Sample Input 2

Sample Output 2

Explanation 2

= [5] and

Here,

does not exist. So,

= 0

SOLUTION

//Complete the following function.

int marks_summation(int* marks, int number_of_students, char gender) {
  //Write your code here.
  int sum = 0;
    
    if(gender == 'b'){
        for(int i = 0; i < number_of_students; i += 2)
            sum += marks[i];
    }
    else{
        for(int i = 1; i < number_of_students; i += 2)
            sum += marks[i];
    }
    
    return sum;
}

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Students Marks Sum in C - Hackerrank Solution