DAY 2: Conditional Statements: Switch | Hackerrank Solution | 10 Days Of Javascript

DAY 2: Conditional Statements: Switch 

Hackerrank Solution 10 Days Of  Javascript

Objective

In this challenge, we learn about switch statements. Check out the attached tutorial for more details.

Task

Complete the getLetter(s) function in the editor. It has one parameter: a string, , consisting of lowercase English alphabetic letters (i.e., a through z). It must return A, B, C, or D depending on the following criteria:

• If the first character in string  is in the set , then return A.
• If the first character in string  is in the set , then return B.
• If the first character in string  is in the set , then return C.
• If the first character in string  is in the set , then return D.

Hint: You can get the letter at some index  in  using the syntax s[i] or s.charAt(i).

Input Format

Stub code in the editor reads a single string denoting  from stdin.

Constraints

• , where  is the length of .
• String  contains lowercase English alphabetic letters (i.e., a through z) only.

Output Format

Return either A, B, C, or D according to the criteria given above.

Sample Input 0

adfgt

Sample Output 0

A

Explanation 0

The first character of string  is a. Because the given criteria stipulate that we print A any time the first character is in , we return A as our answer.

SOLUTION

function getLetter(s) { var letter; // Write your code here switch (s[0]) { case "a": letter="A"; break; case "e": letter="A"; break; case "i": letter="A"; break; case "o": letter="A"; break; case "u": letter="A"; break; case "b": letter="B"; break; case "c": letter="B"; break; case "d": letter="B"; break; case "f": letter="B"; break; case "g": letter="B"; break; case "h": letter="C"; break; case "j": letter="C"; break; case "k": letter="C"; break; case "l": letter="C"; break; case "m": letter="C"; break; default: letter="D"; } return letter; }

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